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	<title>Comments on: The Common-Collector Amplifier Input and Output Resistance &#8211; The Proof</title>
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	<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/</link>
	<description>Electronics Design and Modeling with Emphasis on Analog Design</description>
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		<title>By: Adrian S. Nastase</title>
		<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/#comment-4038</link>
		<dc:creator>Adrian S. Nastase</dc:creator>
		<pubDate>Wed, 14 Sep 2011 07:13:12 +0000</pubDate>
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		<description>Yes, it will come soon.  Keep an eye on MasteringElectronicsDesign.com.  Thank you for visiting.</description>
		<content:encoded><![CDATA[<p>Yes, it will come soon.  Keep an eye on MasteringElectronicsDesign.com.  Thank you for visiting.</p>
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		<title>By: Matthew</title>
		<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/#comment-4033</link>
		<dc:creator>Matthew</dc:creator>
		<pubDate>Tue, 13 Sep 2011 20:16:24 +0000</pubDate>
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		<description>How about the same type of analysis for the common-base amplifier please?</description>
		<content:encoded><![CDATA[<p>How about the same type of analysis for the common-base amplifier please?</p>
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		<title>By: doug</title>
		<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/#comment-3205</link>
		<dc:creator>doug</dc:creator>
		<pubDate>Thu, 10 Mar 2011 09:09:35 +0000</pubDate>
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		<description>thank you for your reply, and apologies for the earlier typos,
as you say, stray capacitances are proving to be a major consideration, ive noticed even on fairly low frequencies, a few hundred kilohertz or so, and with  even a 555 on a good layout, im getting a residual capacitance of around 15 p to 20 p on the timing elements.



thanks again
dougal</description>
		<content:encoded><![CDATA[<p>thank you for your reply, and apologies for the earlier typos,<br />
as you say, stray capacitances are proving to be a major consideration, ive noticed even on fairly low frequencies, a few hundred kilohertz or so, and with  even a 555 on a good layout, im getting a residual capacitance of around 15 p to 20 p on the timing elements.</p>
<p>thanks again<br />
dougal</p>
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	<item>
		<title>By: Adrian S. Nastase</title>
		<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/#comment-3202</link>
		<dc:creator>Adrian S. Nastase</dc:creator>
		<pubDate>Thu, 10 Mar 2011 01:31:15 +0000</pubDate>
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		<description>Yes, although, for high frequency applications, I would add the transistor parasitic capacitances in this hybrid-pi model. At minimum, add C-pi in parallel with r-pi and the feedback capacitance C-miu.</description>
		<content:encoded><![CDATA[<p>Yes, although, for high frequency applications, I would add the transistor parasitic capacitances in this hybrid-pi model. At minimum, add C-pi in parallel with r-pi and the feedback capacitance C-miu.</p>
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		<title>By: doug</title>
		<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/#comment-3199</link>
		<dc:creator>doug</dc:creator>
		<pubDate>Wed, 09 Mar 2011 12:55:30 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=814#comment-3199</guid>
		<description>hi

great tutoriol

i&#039;m matching a simple banpass to a colpits .is transistor output resistance the same as output impedance?</description>
		<content:encoded><![CDATA[<p>hi</p>
<p>great tutoriol</p>
<p>i&#8217;m matching a simple banpass to a colpits .is transistor output resistance the same as output impedance?</p>
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	<item>
		<title>By: Adrian S. Nastase</title>
		<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/#comment-2994</link>
		<dc:creator>Adrian S. Nastase</dc:creator>
		<pubDate>Fri, 11 Feb 2011 22:20:20 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=814#comment-2994</guid>
		<description>Ron, thank you for your comment.  I introduced the source load in calculations for 2 reasons. 

1.  Consistency.  Whenever we study the input and output resistance of a network, it is advised by many to always take into consideration the source resistance.  This resistance may, or may not, influence the result.  In this case, the source resistance does not have any influence on the input resistance.  Instead of cherry-picking when to introduce the source resistance and when not, and confuse the readers in the process, better have it in any system study.  Readers can easily see that it adds to r-pi and can ignore it if they choose so.

2. Signal accuracy.  As figure 3 shows, the calculation of the input resistance is correct, as it is done from the ideal source point of view, through its own resistance.  When we look at a stage output signal level, it is actually the level before its own output resistance.  This level can be affected by the attenuation created by the source resistance and the input resistance of the following stage.  In the case of the common-collector amplifier, the source resistance helps, as it adds to the transistor input resistance. 

So, yes, you are right.  The source resistance is not part of the transistor input resistance per see.  In my opinion it should be there for the reasons I stated.</description>
		<content:encoded><![CDATA[<p>Ron, thank you for your comment.  I introduced the source load in calculations for 2 reasons. </p>
<p>1.  Consistency.  Whenever we study the input and output resistance of a network, it is advised by many to always take into consideration the source resistance.  This resistance may, or may not, influence the result.  In this case, the source resistance does not have any influence on the input resistance.  Instead of cherry-picking when to introduce the source resistance and when not, and confuse the readers in the process, better have it in any system study.  Readers can easily see that it adds to r-pi and can ignore it if they choose so.</p>
<p>2. Signal accuracy.  As figure 3 shows, the calculation of the input resistance is correct, as it is done from the ideal source point of view, through its own resistance.  When we look at a stage output signal level, it is actually the level before its own output resistance.  This level can be affected by the attenuation created by the source resistance and the input resistance of the following stage.  In the case of the common-collector amplifier, the source resistance helps, as it adds to the transistor input resistance. </p>
<p>So, yes, you are right.  The source resistance is not part of the transistor input resistance per see.  In my opinion it should be there for the reasons I stated.</p>
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		<title>By: Ron Harrison</title>
		<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/#comment-2986</link>
		<dc:creator>Ron Harrison</dc:creator>
		<pubDate>Fri, 11 Feb 2011 04:31:56 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=814#comment-2986</guid>
		<description>I understand why you include source resistance in the output resistance equation, but why do you have it in the equation for input resistance? The source resistance is independent of the transistor. The transistor&#039;s input resistance is the load on the source resistance.</description>
		<content:encoded><![CDATA[<p>I understand why you include source resistance in the output resistance equation, but why do you have it in the equation for input resistance? The source resistance is independent of the transistor. The transistor&#8217;s input resistance is the load on the source resistance.</p>
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		<title>By: stephen datsomor</title>
		<link>http://MasteringElectronicsDesign.com/the-common-collector-amplifier-input-and-output-resistance/#comment-1031</link>
		<dc:creator>stephen datsomor</dc:creator>
		<pubDate>Sun, 13 Jun 2010 11:51:21 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=814#comment-1031</guid>
		<description>this allowed me have an understanding of how to derive the input and output resistance</description>
		<content:encoded><![CDATA[<p>this allowed me have an understanding of how to derive the input and output resistance</p>
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