The Non-Inverting Amplifier Output Resistance

December 23rd, 2009 by Adrian S. Nastase


It is customary to consider the output resistance of the non-inverting amplifier as being zero, but why is that? An Op Amp’s own output resistance is in the range of tens of ohms. Still, when we connect the Op Amp in a feedback configuration, the output resistance decreases dramatically. Why?

To answer these questions, let’s calculate the output resistance of the non-inverting amplifier.

It is widely accepted that the output resistance of a device can be calculated using a theoretical test voltage source connected at the device output. The input, or inputs, are connected to ground. Nevertheless, instead of using this method, let’s try a different one: The small signal variation method.

Figure 1 shows the non-inverting amplifier, which drives a load, RL. This circuit has an equivalent Thevenin source as in Figure 2.

non_inverting_amplifier

Figure 1

thevenin_source

Figure 2

From Figure 2, one can see that the output voltage, Vout, can be written as

image003 (1)

If we keep VTH constant and apply small variations to Vout, by varying RL for example, the Vout variation, noted ΔVout can be written as follows:

image004 (2)

Equation (2) shows that, when the load current increases, the load voltage decreases due to the output resistance. They vary in opposite direction and that is why the negative sign that appears in the Rout calculations is canceled out.

Equation (2) also tells us that we can use a small signal variation method to determine Rout. If, instead of ΔVout and ΔIout we write the small signal notation vout and iout, the output resistance becomes

image005 (3)

Let’s apply this method to the non-inverting amplifier.

non_inverting_amplifier

Figure 3

An ideal Op Amp can be represented as a dependent source as in Figure 3. The output of the source has a resistor in series, Ro, which is the Op Amp’s own output resistance. The dependent source is Ao vd, where Ao is the Op Amp open-loop gain and vd is the differential input voltage. The input differential resistance, between the Op Amp inputs, is considered high, so I removed it for simplicity. The same with the common mode input resistances, between the non-inverting input and ground and the inverting input and ground. The non-inverting input is connected to ground, because a fixed value voltage source does not bring any change from a small-signal variation point of view. Thus, we are in line with the general rule that the output resistance of a circuit is calculated with the circuit inputs connected to ground.

Inspecting the loop made by Ao vd, Ro, and RL, vout can be expressed as in the following equation.

image002 (4)

where iout is the small variation load current and if is the small variation feedback current.

The differential voltage vd appears across R1, but with negative sign, so if is

image008 (5)

And vout becomes

image009 (6)

At the same time vd depends on vout.

image010 (7)

After replacing vd in equation (6), the resulting mathematical expression depends on vout and iout as in equation (8).

image011 (8)

Based on (3) and (8) Rout is

iinverting_amplifier_output_resistance1 (9)

Ao is large, about 100000 or 100 dB. Therefore, the second term of the denominator is predominant.

inverting_amplifier_output_resistance2 (10)

This proves that the output resistance of the non-inverting amplifier is

inverting_amplifier_output_resistance3 (11)

where ACL=1+R2/R1 and it is the closed-loop gain of the non-inverting amplifier. For a proof of the closed loop gain read this article, MasteringElectronicsDesign.com:How to Derive the Non-Inverting Amplifier Transfer Function.

As equation (11) shows, the output resistance of the non-inverting amplifier is several orders of magnitude smaller than that of the Op Amp, because Ro is divided by the operational amplifier open loop gain. Therefore, the non-inverting amplifier output resistance can be considered zero.

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11 Comments to “The Non-Inverting Amplifier Output Resistance”

  1. Ady says:

    What will be the output resistance of this circuit if we suppouse that in this circuit(figure 1) RL doesn’t exist, and the resistor R2 will be our load resistance?

  2. treasa says:

    What is the dependence of load resistance on opamp gain?

    • The load and gain do not depend on each other. However, if the load is too small, beyond the op amp output current capability, the output current limit may be triggered. As a consequence, the op amp output signal swing will be reduced.

  3. Paulo says:

    If I have to drive a tone control circuit that needs a source impedance of 38k ohms how to determine the output impedance of the non-inverting amplifier to match this requeriment?

    • If you calculate the output resistance with equation (10) you will find out that it is less than one ohm. So, all you have to do is to add a 38k resistor in series with the non-inverting amplifier output. 38k sounds very high for a source resistor. Are you sure about that value? Your tone control circuit should have high input impedance. Otherwise the 38k resistor will make a voltage divider with the tone control input impedance and the signal will be attenuated accordingly.

  4. Geoff says:

    I have a non-inverting op amp with a 50k ohm feedback resistor and R1 of 1k ohm to ground. The 50kohn resistor is connected to three individual resistors (1k, 25k, 100k) to ground via a SPST. I need to know at each resistor position, is the gain the same? if not, how do I calculate the Gain at each resistor position?

    • You say that the 3 resistors are connected to the 50k. So they can be connected either at the op amp output or the op amp inverting input. If they are connected at the op amp output, the gain is the same no matter which resistor is switched in. They are simply the load of the non-inverting amplifier. If they are connected at the op amp inverting input, the gain is (1 + 50k/(R1||R)) where with R1||R I noted the R1 resistor in parallel with one of the switched in resistors 1k, 25k, 100k.

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