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	Comments on: How to Derive the Instrumentation Amplifier Transfer Function	</title>
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	<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/</link>
	<description>Electronics Design and Modeling with Emphasis on Analog Design</description>
	<lastBuildDate>Thu, 30 Nov 2017 22:47:45 +0000</lastBuildDate>
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		<title>
		By: Adrian S. Nastase		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-41958</link>

		<dc:creator><![CDATA[Adrian S. Nastase]]></dc:creator>
		<pubDate>Thu, 30 Nov 2017 22:47:45 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-41750&quot;&gt;john&lt;/a&gt;.

You can use INA126 (Texas Instruments). RG is the gain resistor. With RG = 162 ohms, 1% tolerance, the gain is 500.]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-41750">john</a>.</p>
<p>You can use INA126 (Texas Instruments). RG is the gain resistor. With RG = 162 ohms, 1% tolerance, the gain is 500.</p>
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		<title>
		By: Hasrat Ali Anjum		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-41803</link>

		<dc:creator><![CDATA[Hasrat Ali Anjum]]></dc:creator>
		<pubDate>Sat, 25 Nov 2017 13:43:58 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-3043&quot;&gt;Grant&lt;/a&gt;.

Ley us U3 non inverting terminal voltage Vp then
      Vp=V11*R2/(R1+R2).      {by voltage divider rule}
&#038; Inverting terminal is connected R3 with V12 voltage
  Now. R4=R2,R3=R1,
       Apply superposition theorem 
       (1).   Vp=0 then U3 act like a inverting amplifier
    So Vout(1)&#039;= --(R4/R3)V12,=--(R2/R1)V12,
        (2) V12=0 then U3 act like a non-inverting amplifier so,  Vout(1)&#039;&#039;=Vp*(1+R4/R3)=(1+R2/R1)Vp
      =(1+R2/R1)(R2/R1+R2)*V11
      Vout(1)&#039;&#039; =   V11*(R2/R1)
       Vout1=Vout(1)&#039;+Vout(1)&#039;&#039;
                =R2/R1*(V11--V12)]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-3043">Grant</a>.</p>
<p>Ley us U3 non inverting terminal voltage Vp then<br />
      Vp=V11*R2/(R1+R2).      {by voltage divider rule}<br />
&amp; Inverting terminal is connected R3 with V12 voltage<br />
  Now. R4=R2,R3=R1,<br />
       Apply superposition theorem<br />
       (1).   Vp=0 then U3 act like a inverting amplifier<br />
    So Vout(1)&#8217;= &#8211;(R4/R3)V12,=&#8211;(R2/R1)V12,<br />
        (2) V12=0 then U3 act like a non-inverting amplifier so,  Vout(1)&#8221;=Vp*(1+R4/R3)=(1+R2/R1)Vp<br />
      =(1+R2/R1)(R2/R1+R2)*V11<br />
      Vout(1)&#8221; =   V11*(R2/R1)<br />
       Vout1=Vout(1)&#8217;+Vout(1)&#8221;<br />
                =R2/R1*(V11&#8211;V12)</p>
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		<title>
		By: john		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-41750</link>

		<dc:creator><![CDATA[john]]></dc:creator>
		<pubDate>Thu, 16 Nov 2017 14:38:43 +0000</pubDate>
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					<description><![CDATA[hello,how to design an intrumentations amplifers to satisfy a fixed differential voltage gain of Af=500? please reply me as soon as possible]]></description>
			<content:encoded><![CDATA[<p>hello,how to design an intrumentations amplifers to satisfy a fixed differential voltage gain of Af=500? please reply me as soon as possible</p>
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		<title>
		By: Tasnim Taleeb		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-41635</link>

		<dc:creator><![CDATA[Tasnim Taleeb]]></dc:creator>
		<pubDate>Fri, 27 Oct 2017 19:34:06 +0000</pubDate>
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					<description><![CDATA[Prove that the gain of the INA 126 amplifier is equal to ? ?
?? ????/??]]></description>
			<content:encoded><![CDATA[<p>Prove that the gain of the INA 126 amplifier is equal to ? ?<br />
?? ????/??</p>
]]></content:encoded>
		
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		<item>
		<title>
		By: Adrian S. Nastase		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-35435</link>

		<dc:creator><![CDATA[Adrian S. Nastase]]></dc:creator>
		<pubDate>Thu, 19 May 2016 05:35:56 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-35048&quot;&gt;Marwah&lt;/a&gt;.

I don&#039;t understand this question. You need to reformulate it.]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-35048">Marwah</a>.</p>
<p>I don&#8217;t understand this question. You need to reformulate it.</p>
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		<title>
		By: Marwah		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-35048</link>

		<dc:creator><![CDATA[Marwah]]></dc:creator>
		<pubDate>Sun, 01 May 2016 08:47:43 +0000</pubDate>
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					<description><![CDATA[How to drive common mode gain of the first stage?]]></description>
			<content:encoded><![CDATA[<p>How to drive common mode gain of the first stage?</p>
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			</item>
		<item>
		<title>
		By: Adrian S. Nastase		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-33601</link>

		<dc:creator><![CDATA[Adrian S. Nastase]]></dc:creator>
		<pubDate>Thu, 25 Feb 2016 06:27:01 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-28309&quot;&gt;ashish burande&lt;/a&gt;.

I think my article shows that. You need to choose an instrumentation amplifier (go to digikey.com) and look in the data sheet for the transfer function. Should be similar with what I describe here. You need to calculate a resistor value to set the gain. 1 mV is a small signal. You need to choose a low noise amplifier with low offset.]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-28309">ashish burande</a>.</p>
<p>I think my article shows that. You need to choose an instrumentation amplifier (go to digikey.com) and look in the data sheet for the transfer function. Should be similar with what I describe here. You need to calculate a resistor value to set the gain. 1 mV is a small signal. You need to choose a low noise amplifier with low offset.</p>
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			</item>
		<item>
		<title>
		By: Adrian S. Nastase		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-33598</link>

		<dc:creator><![CDATA[Adrian S. Nastase]]></dc:creator>
		<pubDate>Thu, 25 Feb 2016 05:58:31 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-33387&quot;&gt;Saif&lt;/a&gt;.

I would use 10kohm resistors.]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-33387">Saif</a>.</p>
<p>I would use 10kohm resistors.</p>
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		<item>
		<title>
		By: Saif		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-33411</link>

		<dc:creator><![CDATA[Saif]]></dc:creator>
		<pubDate>Tue, 16 Feb 2016 22:04:58 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-33187&quot;&gt;Adrian S. Nastase&lt;/a&gt;.

I use 200kohm for every resistors. Is the value make sense ? 

I am now in the process of designing signal conditioning circuit for thermistor. 
The temperature range is between 0-100 deg C. 
So I make the maximum temperature which is 100 deg C as maximum output voltage which is 5V. 

The value for V1 measured is 131.35mV
the value for V2 measured is 27.41mV

Then I calculate using your equation by substitute the Vo as 5V
and I find the value of RG is about 8491ohm.

Is my calculation is correct or not ?]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-33187">Adrian S. Nastase</a>.</p>
<p>I use 200kohm for every resistors. Is the value make sense ? </p>
<p>I am now in the process of designing signal conditioning circuit for thermistor.<br />
The temperature range is between 0-100 deg C.<br />
So I make the maximum temperature which is 100 deg C as maximum output voltage which is 5V. </p>
<p>The value for V1 measured is 131.35mV<br />
the value for V2 measured is 27.41mV</p>
<p>Then I calculate using your equation by substitute the Vo as 5V<br />
and I find the value of RG is about 8491ohm.</p>
<p>Is my calculation is correct or not ?</p>
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		<item>
		<title>
		By: Saif		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-instrumentation-amplifier-transfer-function/#comment-33387</link>

		<dc:creator><![CDATA[Saif]]></dc:creator>
		<pubDate>Tue, 16 Feb 2016 00:43:48 +0000</pubDate>
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					<description><![CDATA[Hello.
Very helpful articles.
Im in the process of design my signal conditioning circuit for thermistor. I do need this amplifier since the output from Wheatstone Bridge is in mV. 
Is it make sense the resistor I used for this amplifier is all 200k ohm ?
Is it too big ?]]></description>
			<content:encoded><![CDATA[<p>Hello.<br />
Very helpful articles.<br />
Im in the process of design my signal conditioning circuit for thermistor. I do need this amplifier since the output from Wheatstone Bridge is in mV.<br />
Is it make sense the resistor I used for this amplifier is all 200k ohm ?<br />
Is it too big ?</p>
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