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	Comments on: How to Derive the Summing Amplifier Transfer Function	</title>
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	<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/</link>
	<description>Electronics Design and Modeling with Emphasis on Analog Design</description>
	<lastBuildDate>Thu, 05 Oct 2017 23:42:25 +0000</lastBuildDate>
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	<item>
		<title>
		By: Kurtis		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-41482</link>

		<dc:creator><![CDATA[Kurtis]]></dc:creator>
		<pubDate>Thu, 05 Oct 2017 23:42:25 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=413#comment-41482</guid>

					<description><![CDATA[Thank you! As an ME student having to take a circuits class, this has made things make much more sense.]]></description>
			<content:encoded><![CDATA[<p>Thank you! As an ME student having to take a circuits class, this has made things make much more sense.</p>
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		<title>
		By: Op-amp Summing Amplifier &#124; PCS		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-27163</link>

		<dc:creator><![CDATA[Op-amp Summing Amplifier &#124; PCS]]></dc:creator>
		<pubDate>Fri, 28 Aug 2015 08:33:14 +0000</pubDate>
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					<description><![CDATA[[&#8230;] Op-amp Summing Amplifier on Electronics-tutorials Op-amp non Inverting Summing Amplifier on Masteringelectronicsdesign [&#8230;]]]></description>
			<content:encoded><![CDATA[<p>[&#8230;] Op-amp Summing Amplifier on Electronics-tutorials Op-amp non Inverting Summing Amplifier on Masteringelectronicsdesign [&#8230;]</p>
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		<item>
		<title>
		By: Adrian S. Nastase		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-2766</link>

		<dc:creator><![CDATA[Adrian S. Nastase]]></dc:creator>
		<pubDate>Sun, 28 Nov 2010 05:45:01 +0000</pubDate>
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					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-2183&quot;&gt;Godwin&lt;/a&gt;.

Thank you for your comment Godwin.  I am glad that this website helped you.]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-2183">Godwin</a>.</p>
<p>Thank you for your comment Godwin.  I am glad that this website helped you.</p>
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		<item>
		<title>
		By: Godwin		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-2183</link>

		<dc:creator><![CDATA[Godwin]]></dc:creator>
		<pubDate>Fri, 19 Nov 2010 06:39:57 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=413#comment-2183</guid>

					<description><![CDATA[I am glad I fond this site!. Very easy to understand. All of the books only show inverting summing amplifiers but I need to design a non-inverting one. I thought it was complicated before. But when I saw your transfer function, I immediately realized that you used the Superposition Theorem to get the solution. Thanks a lot!]]></description>
			<content:encoded><![CDATA[<p>I am glad I fond this site!. Very easy to understand. All of the books only show inverting summing amplifiers but I need to design a non-inverting one. I thought it was complicated before. But when I saw your transfer function, I immediately realized that you used the Superposition Theorem to get the solution. Thanks a lot!</p>
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		<item>
		<title>
		By: Adrian S. Nastase		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-1087</link>

		<dc:creator><![CDATA[Adrian S. Nastase]]></dc:creator>
		<pubDate>Sat, 03 Jul 2010 07:35:36 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=413#comment-1087</guid>

					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-1086&quot;&gt;Kibblekly&lt;/a&gt;.

I believe you ask about sending personal messages to the other users of this website. For this you need a forum. I do not have a forum yet. I plan to have one in the future. If any of you would like to be forum administrator(s) please let me know. In the mean time you can post responses to other people&#039;s comments.]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-1086">Kibblekly</a>.</p>
<p>I believe you ask about sending personal messages to the other users of this website. For this you need a forum. I do not have a forum yet. I plan to have one in the future. If any of you would like to be forum administrator(s) please let me know. In the mean time you can post responses to other people&#8217;s comments.</p>
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		<item>
		<title>
		By: Kibblekly		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-1086</link>

		<dc:creator><![CDATA[Kibblekly]]></dc:creator>
		<pubDate>Fri, 02 Jul 2010 16:13:46 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=413#comment-1086</guid>

					<description><![CDATA[How I can write PM to other users? Thanx]]></description>
			<content:encoded><![CDATA[<p>How I can write PM to other users? Thanx</p>
]]></content:encoded>
		
			</item>
		<item>
		<title>
		By: Adrian S. Nastase		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-920</link>

		<dc:creator><![CDATA[Adrian S. Nastase]]></dc:creator>
		<pubDate>Mon, 10 May 2010 20:26:05 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=413#comment-920</guid>

					<description><![CDATA[Thanks Aries.  Glad you find this website useful.]]></description>
			<content:encoded><![CDATA[<p>Thanks Aries.  Glad you find this website useful.</p>
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		<item>
		<title>
		By: Aries		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-891</link>

		<dc:creator><![CDATA[Aries]]></dc:creator>
		<pubDate>Thu, 06 May 2010 16:15:30 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=413#comment-891</guid>

					<description><![CDATA[Very helpful source and it help me a lot especially when some of my lecture notes did not really help me a lot in understanding fully of some particular topic related. Thank you very much for the blog. Credit for you.

Thanks.]]></description>
			<content:encoded><![CDATA[<p>Very helpful source and it help me a lot especially when some of my lecture notes did not really help me a lot in understanding fully of some particular topic related. Thank you very much for the blog. Credit for you.</p>
<p>Thanks.</p>
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			</item>
		<item>
		<title>
		By: Adrian S. Nastase		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-777</link>

		<dc:creator><![CDATA[Adrian S. Nastase]]></dc:creator>
		<pubDate>Wed, 07 Apr 2010 20:45:19 +0000</pubDate>
		<guid isPermaLink="false">http://masteringelectronicsdesign.com/?p=413#comment-777</guid>

					<description><![CDATA[In reply to &lt;a href=&quot;https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-775&quot;&gt;david&lt;/a&gt;.

Thank you David.  I really appreciate that. 
As for your question, if you connect R3 to a reference voltage, say V3, the circuit output is shifted by   –V3*R4/R3.  The new transfer function is:

Vout = ((V1*R2/(R1+R2) + V2*R1/(R1+R2)) * (1+R4/R3) - V3*R4/R3

Hope this helps for now.  I will write a short article to prove this.  If you wish, please use the RSS or Facebook subscription to be notified.
===============
&lt;strong&gt;Update&lt;/strong&gt;: I published this article. You can find it here:
&lt;a href=&quot;http://masteringelectronicsdesign.com/a-summing-and-differential-amplifier-with-one-op-amp/&quot; rel=&quot;nofollow&quot;&gt;A Summing and Differential Amplifier with One Op Amp&lt;/a&gt;]]></description>
			<content:encoded><![CDATA[<p>In reply to <a href="https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-775">david</a>.</p>
<p>Thank you David.  I really appreciate that.<br />
As for your question, if you connect R3 to a reference voltage, say V3, the circuit output is shifted by   –V3*R4/R3.  The new transfer function is:</p>
<p>Vout = ((V1*R2/(R1+R2) + V2*R1/(R1+R2)) * (1+R4/R3) &#8211; V3*R4/R3</p>
<p>Hope this helps for now.  I will write a short article to prove this.  If you wish, please use the RSS or Facebook subscription to be notified.<br />
===============<br />
<strong>Update</strong>: I published this article. You can find it here:<br />
<a href="http://masteringelectronicsdesign.com/a-summing-and-differential-amplifier-with-one-op-amp/" rel="nofollow">A Summing and Differential Amplifier with One Op Amp</a></p>
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			</item>
		<item>
		<title>
		By: david		</title>
		<link>https://masteringelectronicsdesign.com/how-to-derive-the-summing-amplifier-transfer-function/#comment-775</link>

		<dc:creator><![CDATA[david]]></dc:creator>
		<pubDate>Wed, 07 Apr 2010 15:33:23 +0000</pubDate>
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					<description><![CDATA[Mr. Nastase, this is a great site full of practical and useful information. Thank you for putting this up! I do have a question that I am sure you can answer. How does the transfer function of Figure 1 change if R3 is tied to a reference voltage instead of zero potential? Thank you!]]></description>
			<content:encoded><![CDATA[<p>Mr. Nastase, this is a great site full of practical and useful information. Thank you for putting this up! I do have a question that I am sure you can answer. How does the transfer function of Figure 1 change if R3 is tied to a reference voltage instead of zero potential? Thank you!</p>
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