Comments on: How to Derive the Differential Amplifier Transfer Function

By: Adrian S. Nastase

Adrian S. Nastase — Fri, 19 Jan 2024 04:35:47 +0000

In reply to Jerry Godson. Simply replace V1 with Vin.

By: Jerry Godson

Jerry Godson — Fri, 27 Oct 2023 03:58:38 +0000

What can I do to make the transfer function in terms of vin?

By: Ricky

Ricky — Sun, 15 May 2016 10:58:01 +0000

Thanks alot, you explained better than my lectuer.

By: Santosh

Santosh — Thu, 09 Apr 2015 05:37:43 +0000

Thanks for explanation……………

By: rakhi kashyap

rakhi kashyap — Mon, 23 Feb 2015 11:32:22 +0000

many many thanx

By: Adrian S. Nastase

Adrian S. Nastase — Wed, 22 Oct 2014 20:26:26 +0000

In reply to Merkhav.

If you perform some broad search on internet, you should find some info. Also, Wikipedia is a good source for filters.

Manufacturers like Texas Instruments, Linear Technology and Analog Devices have good articles about filters as well. Do a search on their websites.

Other than that, try to find some textbooks that describe the filters.

Sometime in the future I will write a series about filters.

By: Merkhav

Merkhav — Tue, 21 Oct 2014 21:42:14 +0000

Where can I find how to derive the bandpass filter and band reject filter transfer function?

By: Matt

Matt — Sat, 21 Jun 2014 01:22:52 +0000

Many thanks

By: Adrian S. Nastase

Adrian S. Nastase — Sat, 27 Jul 2013 04:25:23 +0000

In reply to Berns Buenaobra. Correct for R2=R4 and R1=R3. Still, this is just one case. This article shows the derivation of the general form of the transfer function because it can be used to build other circuits, not only a simple difference. For example, one can design a unipolar to bipolar converter as in this article I published some time ago: Design a Unipolar to Bipolar Converter for a Unipolar Voltage Output DAC. Thank you for your comment.

By: Berns Buenaobra

Berns Buenaobra — Wed, 24 Jul 2013 21:47:13 +0000

We could still come to as close to an ideal difference amplifier – that is the difference between the non-inverting input with the inverting input is multiplied by a simple gain G=R4/R3 this is done by design so that R2=R4 and R1=R3 then the entire derived equation reduces to Vout=DeltaVin*G=(V1-V2)*(R4/R3)